Answer:
P = 9 is the max value
Step-by-step explanation:
Sketch
2x + 4y = 10
with x- intercept = (5, 0) and y- intercept (0, 2.5)
x + 9y = 12
with x- intercept = (12, 0) and y- intercept = (0, [tex]\frac{4}{3}[/tex] )
Solve
2x + 4y = 10 and x + 9y = 12 to find the point of intersection at (3, 1)
The region corresponding to the solution of the system of constraints
Has vertices at (0, [tex]\frac{4}{3}[/tex]), (0, 0) , (5, 0) and (3, 1)
Now evaluate the objective function at each vertex.
(0, 0) can be excluded as it will not give a maximum
(5, 0) → P = 5 + 0 = 5
(0, [tex]\frac{4}{3}[/tex]) → 0 + 8 = 8
(3, 1) → 3 + 6(1) = 3 + 6 = 9 ← maximum value
Thus the maximum value is 9 when x = 3 and y = 1
