Answer:
Drew saves a distance of [tex]1\ mile[/tex] by taking the shortcut.
Step-by-step explanation:
Here is an image of the routes.
We have drawn it assigning the signs NSEW where N=North,S=South ,E=East and W=West.
Now the total distance covered by Drew = OA+AB+BC [tex]=(1.25+0.75+0.25)=2.25\ miles[/tex]
We see by joining C with O it has a shortcut.
And it forms a right angled triangle.
[tex]\triangle ODC[/tex] , [tex]90(degrees)[/tex] at D.
By using Pythagoras theorem we can find the shortcut distance.
OC is the hypotenuse and [tex]OC=\sqrt{1^2+0.75^2} = 1.25\ miles[/tex]
So Drew saves [tex](2.25-1.25)=1\ miles[/tex] of distance following the advice of his friend and opting for the shortcut route.