Respuesta :
Answer:
Slope of the function is [tex]=3.75[/tex],Y-intercept [tex]=20[/tex].
The function is [tex]y=3.75(x)+20[/tex] with initial value[tex]=20[/tex],Jordan puts [tex]\$3.75[/tex] each week andthe amount saved by Jordan after [tex]52[/tex] week [tex]=215\$[/tex].
Step-by-step explanation:
To understand the slope and y-intercept lets assign [tex]x[/tex] as number of weeks and [tex]y[/tex] as the money saved by Jordan.
Jordan is already having a sum of [tex]\$20[/tex] inside the money bank so in [tex]0[/tex] week the amount is [tex]\$20[/tex] can be written as [tex](x,y) =(0,20)[/tex] in coordinate form.
SImilarly
We have [tex](x,y) =(0,20)[/tex]and [tex](x_1,y_1) =(25,113.75)[/tex]
Part A:
The function is [tex]y=m(x)+b[/tex]
From point-slope form,we have slope (m)
and [tex]m=\frac{y_1-y}{x_1-x}[/tex],plugging the values of the points.
[tex]m=\frac{113.75-20}{25-0}=3.75[/tex]
Y-intercept of this function is the constant term or the money of [tex]\$20[/tex] that is already inside the money bank.
We can also calculate y-intercept by arranging the function as [tex]b=y-m(x)[/tex] choosing any [tex](x_1,y_1) = (25,113.75)[/tex] coordinate and here [tex]b[/tex] is the y-intercept.
The result will be same.
Part B:
The equation [tex]y=3.75(x)[/tex] can represent the function described.
And the initial value is the y-intercept [tex]=\$20[/tex]
Jordan puts [tex]3.75[/tex] in his bank each week.
After [tex]52[/tex] week the amount saved by Jordan ,here [tex]x=52[/tex],as the x-variable is the number of weeks.
Plugging the value of [tex]x=52[/tex] in [tex]y=m(x)+b[/tex] where [tex]m=3.75[/tex] so the equation becomes [tex]y=3.75(x)+20[/tex]
[tex]y=3.75(x)+20 =3.75(52)+20=\$215[/tex]
So basically the function is [tex]y=3.75(x)+20[/tex] and the amount saved by Jordan after [tex]52[/tex] week [tex]=215\$[/tex].