Question

What is the slope-intercept form of the equation of the line that passes through the point (-6. 1) and is perpendicular to the
graph of 2x + 3y = -5?

Answer 1

Answer:

Perpendicular means that,second gradient equals to first one as:

$- \frac{1}{m}$

So,conducting the second equation to the form y=mx+c: 3y= -2x-5

$y = - \frac {2}{3}x - \frac{5}{3}$

So it's gradient is

$- \frac{2}{3}$

converting to

$- \frac{1}{m}$

equals to 1.5 or at least

$\frac{3}{2}$

Y find the equation of the first line you've got to use the formula: y-y1=m (x-x1)

y-1=1.5 (x+6)

y-1=1.5x+9

y=1.5x+10 is the equation of the first line.