Respuesta :
Answer:
The population of town after 10 years is 8300 unit .
Step-by-step explanation:
Given as :
The rate of decrease of population of town = 4%
The initial population of town = 12,500 unit
Let The population of town after 10 years = P
So ,
The population of town after n years = initial population × [tex](1-\frac{Rate}{100})^{n}[/tex]
Or, The population of town after 10 years = 12,500 × [tex](1-\frac{4}{100})^{10}[/tex]
Or, The population of town after 10 years = 12,500 × [tex](0.96)^{10}[/tex]
∴ The population of town after 10 years = 12,500 × 0.664 = 8300 unit
Hence The population of town after 10 years is 8300 unit . Answer
The population after 10 years will be 8310 approximately.
Option - 4
SOLUTION:
Given that, the population of a town is decreasing by [tex]4\%[/tex] per year and started with 12,500 residents,
We have to find its projected population in 10 years. We can use the formula
[tex]\text { present population }=\text { previous population } \times\left(1-\frac{\text {rate}}{100}\right)^{\text {times\times period }}[/tex]
Then, population after 10 years [tex]=12500 \times\left(1-\frac{4}{100}\right)^{10}[/tex]
[tex]\begin{array}{l}{\Rightarrow 12500 \times(1-0.04)^{10}} \\\\ {\Rightarrow 12500 \times 0.96^{10}} \\\\ {\Rightarrow 12500 \times 0.6648} \\\\ {\Rightarrow 8310.407\rightarrow 8310.407\approx 8310}\end{array}[/tex]
ROUNDING OFF RULES:
Step 1: First, look at the digit to the immediate right of rounding off the digit
Step 2: If that digit is less than 5, do not change the rounding digit but drop all digits to the right of it.
Step 3: If that digit is greater than or equal to five, add one to the rounding digit and drop all digits to the right of it.