Question

A runner taking part in the 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of 45 m. The runner starts the race at a constant speed. If she completes the 200 m dash in 21.6 s and runs at constant speed throughout the race, what is the magnitude of her centripetal acceleration (in m/s2) as she runs the curved portion of the track?

Answer 1

Answer:

$a_c=1.05m/s^2$

Explanation:

Given:

$L=200m$,$t=21.6s$,$r=45m$

The velocity of the motion

$v=\frac{L}{t}=\frac{200m}{21.6s}$

$v=9.26m/s$

Now the acceleration centripetal is given by:

$a_c=\frac{v^2}{r}$

$a_c=\frac{(9.26m/s)^2}{45m}$

$a_c=1.05m/s^2$