The function f(x)=5^(x−1) is shown on the coordinate plane.

Select from the drop-down menus to correctly describe the end behavior of ​

f(x)


As x decreases without bound, the graph of

f(x)


A. approaches y = 0

B. increases without bound

C. decreases without bound


As x increases without bound, the graph of

f(x)


A. approaches y = 0

B. increases without bound

C. decreases without bound

The function fx5x1 is shown on the coordinate planeSelect from the dropdown menus to correctly describe the end behavior of fxAs x decreases without bound the g class=

Respuesta :

DeanR

Just from the figure,

As x decreases, y approaches 0

As x increases, y increases without bound

Answer:

The answer is:

As x decreases without bound, the graph of f(x) approaches y = 0

As x increases without bound, the graph of  f(x) increases without bound

Step-by-step explanation:

When x goes -∞;

[tex]\lim_{x \to -\infty} f(x) =5^{x-1}=0[/tex]

When x goes to ∞;

[tex]\lim_{x \to \infty} f(x)=5^{x-1}= \infty[/tex]

Therefore the solution is;

As x decreases without bound, the graph of f(x) approaches y = 0

As x increases without bound, the graph of  f(x) increases without bound

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