Question

Use the following table of a school bus during morning pickups to calculate its average speed between 0h and 2.34 h. ​

Answer 1

Answer : The average speed of between 0 hr and 2.34 hr is, 9.820 km/hr

Explanation :

Average speed : It is defined as the ratio total distance to total time.

Formula used :

$\text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}$

Now put all the given values in the above formula, we get:

$\text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}$

$\text{Average speed}=\frac{(0.0+1.2+2.8+4.2+16.34)km}{(0.000+0.024+0.051+0.084+2.34)hr}$

$\text{Average speed}=\frac{24.54km}{2.499hr}$

$\text{Average speed}=9.820km/hr$

Therefore, the average speed of between 0 hr and 2.34 hr is, 9.820 km/hr

Answer 2

Answer:

6.983 km/hr

Explanation:

This problem asks for the the average rate of change, which is Δy/Δx. In this case, the time represents x, and the position represents y. The average rate of change is (16.34 - 0.0)/(2.34 - 0.000) ≈ 6.983 km/hr