Explanation:
Let [tex]t_{1f}[/tex] be the low temperature in fahrenheit.
Let [tex]t_{2f}[/tex] be the high temperature in fahrenheit.
Let [tex]t_{1k}[/tex] be the low temperature in Kelvin.
Let [tex]t_{2k}[/tex] be the high temperature in Kelvin.
Question a:
As we know [tex]\frac{c}{5}=\frac{F-32}{9}[/tex]
[tex]\frac{1.15}{5}=\frac{t_{1f}-32}{9}[/tex]
[tex]t_{1f}=34.07^{0}F[/tex]
[tex]\frac{31.4}{5}=\frac{t_{2f}-32}{9}[/tex]
[tex]t_{2f}=88.52^{0}F[/tex]
So the difference is [tex]t_{2f}-t_{1f}=54.45^{0}F[/tex]
Question b:
As we know [tex]c+273=k[/tex]
[tex]1.15+273=t_{1k}[/tex]
[tex]t_{1k}=274.15K[/tex]
[tex]31.4+273=t_{2k}[/tex]
[tex]t_{2k}=304.4K[/tex]
So the difference is [tex]t_{2k}-t_{1k}=30.25K[/tex]