Answer:
[tex]V_2=32.7mL[/tex]
Explanation:
Given
[tex]T_1=26+273=299K[/tex], [tex]T_2=-87+273=186K[/tex]
[tex]P_1=0.115atm*\frac{760mmHg}{1atm}=87.4 mmHg[/tex],[tex]P_2=755mmHg[/tex]
[tex]V_1=455mL[/tex]
Using the Law of gases to solve the final volume in milliliters
[tex]\frac{P_1*V_1}{T_1}= \frac{P_2*V_2}{T_2}[/tex]
Solve to V2
[tex]V_2=\frac{T_2*P_1*V_1}{T_1*P_2}[/tex]
[tex]V_2=\frac{186K*87.4mmHg*455mL}{299K*755mmHg}[/tex]
[tex]V_2=32.7mL[/tex]