Answer:
P(A or B) is 0.72
Step-by-step explanation:
Given : P(A) = 0.3 and P(B) = 0.6
To Find:P(A or B) = P(A∪B)
Solution :
We are given that A and B are two independent events
Property : If A and B are independent events then [tex]P(A \cap B) = P(A) \times P(B)[/tex]
So, [tex]P(A \cap B) = P(A) \times P(B)[/tex]
[tex]P(A \cap B) =0.3 \times 0.6[/tex]
[tex]P(A \cap B) =0.18[/tex]
Formula : [tex]P(A \cup B)=P(A)+P(B)-P(A \cap B)[/tex]
[tex]P(A \cup B)=0.3+0.6-0.18[/tex]
[tex]P(A \cup B)=0.72[/tex]
Hence P(A or B) is 0.72