Question

The midpoint pf ab is m ( 0,-1) . If the coordinates of a are (4,3), what are the coordinates of b

Answer 1

Answer:

The coordinate of point B is (-4, -5).

Step-by-step explanation:

Given:

M is the midpoint of a AB

let $A = (4,3) = (x1,y1)\ say\\ B = (x2,y2)\ say\\M = (0,-1)= (x,y)\ say$

To Find:

$B = (x2,y2) = ?$

Solution:

As M is the midpoint of $\vec{AB}$ so applying midpoint formula we have

X coordinate i.e x and Y coordinate i.e y given by

$x = \frac{x1 + x2}{2}\\ and\\y = \frac{y1 + y2}{2}$

On substituting the values for X1, X2, X and Y we will get

$0 =\frac{4 + x2}{2}\\0 = 4 + x2\\x2 = -4\\and\\-1 = \frac{3 + y2}{2} \\-2 = 3 + y2\\y2 = -2 - 3\\y2 = -5$

So the coordinates for B (x2,y2) is B (-4,-5).