Question

write the equation of a line with the same slope as y-3=-2(x+1) and a solution of (4,10) in slope intercept form

Answer 1

Answer:

$y=-2x+18$

Step-by-step explanation:

We start by noticing that the given line: $y-3=-2\,(x+1)$ is given in "point slope" form, where the slope (m) is "-2".

We need therefore another line with same slope (m = -2) and which goes through the point (4, 10), which will make it solution of the line equation.

We can use the general form of a line in "point slope" form with slope "m" , and going through the point $(x_0,y_0)$ on the plane as:

$y-y_0=m\,(x-x_0)$

For our case: m = -2 and $y-y_0=m\,(x-x_0)$ = (4, 10) this becomes:

$y-y_0=m\,(x-x_0)\\y-10=-2\,(x-4)\\y-10=-2x+8\\y=-2x+8+10\\y=-2x+18$