Question

2. George estimates that each bale of hay in his field weighs 62.5 pounds on
average. There are 892 bales to be picked up. If his truck can carry 8 tons on
one trip, how many trips will he have to make to move his bales?

Answer 1

Answer:

4 trips

Step-by-step explanation:

there are 892 bales of hay

each one weighs about 62.5 pounds

892 * 62.5 = 55,750

George's truck can only carry 8 tons

1 ton = 2,000 pounds

2,000 * 8 = 16,000 pounds

So,

55,750 / 16,000 = 3.484375

But since you can't make 3.484375 trips in a truck, round it up.

3.484375 rounded up equals 4

George has to take 4 trips

Answer 2

Answer:

It's 3.4 so  4 trips is your answer.

Step-by-step explanation:

First, the bales are 62.5 lbs & there are 892 of them, so multiply them, 892 X 62.5=equaling 55,750 lbs.

Second, there are 2,000 lbs in one ton and his truck can hold 8 tons. Take

2,000 X 8=16 then, take your 55,750 lbs and divide it by the 16 tons.

Lastly, 55,750/16= 3.4. So, it will take George  4 trips since there was a couple of bales left over.

Hope I didn't lose ya.