Answer:
For 8000 g of water the amount of chlorine in the pool is 20 mg .
Step-by-step explanation:
Given as :
The pool has 2.5 mg of chlorine per liter of water
I.e The pool has 2.5 mg of chlorine per 1000 g of water
Let The amount of pool in 8000 g of water be x mg
So, From unitary method
∵ For 1000 g of water , The pool has 2.5 mg of chlorine
so, For 1 g of water , The pool has [tex]\frac{2.5}{1000}[/tex] mg of chlorine
∴ For 8000 g of water , The pool has [tex]\frac{2.5}{1000}[/tex] × 8000 mg of chlorine
I,e For 8000 g of water , The pool has 2.5 × 8 mg of chlorine
Or, For 8000 g of water , The pool has 20 mg of chlorine
Hence for 8000 g of water the amount of chlorine in the pool is 20 mg . Answer