[tex]\boxed{f(x=0.5)=16}[/tex]
In this exercise, we have a function [tex]f(x)[/tex] that varies directly with x. Direct variation is a case of variation expresses as the following form:
[tex]f(x)=kx \\ \\ For \ a \ non-constant \ zero[/tex]
This indicates that [tex]f(x)[/tex] incrases as x increases. Moreover, this is a line with slope [tex]k[/tex] and passes through the origin. So finding [tex]k[/tex]:
[tex]f(x)=kx \\ \\ Isolating \ k: \\ \\ k=\frac{f(5)}{5} \\ \\ k=\frac{160}{5}=32[/tex]
So:
[tex]f(x)=32x[/tex]
Finally, when x = 0.5, then
[tex]f(x=0.5)=32(0.5) \\ \\ \boxed{f(x=0.5)=16}[/tex]
System of equations: https://brainly.com/question/13799715
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