The tower is 61.65 meters tall.
SOLUTION:
Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.
At the same time, a nearby tower casts a shadow that is 36.25 m long.
We have to find height of the tower.
Now, we know that,
[tex]2.5 \mathrm{m} \text { tall } \rightarrow 1.47 \text { long shadow }[/tex]
Then, (let it be) n meter tall [tex]\rightarrow[/tex] 36.25 long shadow
So, by cross multiplication method,
[tex]\Rightarrow \frac{2.5}{1.47}=\frac{n}{36.25}[/tex]
This can be written as,
[tex]\Rightarrow 36.25 \times 2.5=1.47 \times n \rightarrow 1.47 n=90.625 \rightarrow n=61.649 \rightarrow n=61.65 \text{ m}[/tex]
Cross multiplications steps: (To find Single Variable)