A linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) is:
[tex]y=\frac{1}{4}x-\frac{9}{4}[/tex]
Step-by-step explanation:
Given points are:
(-11, -5) = (x1,y1)
(1, -2) = (x2,y2)
We have to find the slope first
[tex]m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-2-(-5)}{1-(-11)}\\m=\frac{-2+5}{12}\\m=\frac{3}{12}\\m=\frac{1}{4}[/tex]
Slope-intercept form is:
[tex]y=mx+b[/tex]
Put the value of slope
[tex]y=\frac{1}{4}x+b[/tex]
To find the value of b, putting the point (1 -2) in equation
[tex]-2=\frac{1}{4}(1)+b\\-2=\frac{1}{4}+b\\-2-\frac{1}{4}=b\\b=\frac{-8-1}{4} \\b=\frac{-9}{4}[/tex]
Putting the values of b and m
[tex]y=\frac{1}{4}x-\frac{9}{4}[/tex]
A linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) is:
[tex]y=\frac{1}{4}x-\frac{9}{4}[/tex]
Keywords: Equation of line, slope-intercept form
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