Respuesta :

A linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) is:

[tex]y=\frac{1}{4}x-\frac{9}{4}[/tex]

Step-by-step explanation:

Given points are:

(-11, -5) = (x1,y1)

(1, -2) = (x2,y2)

We have to find the slope first

[tex]m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-2-(-5)}{1-(-11)}\\m=\frac{-2+5}{12}\\m=\frac{3}{12}\\m=\frac{1}{4}[/tex]

Slope-intercept form is:

[tex]y=mx+b[/tex]

Put the value of slope

[tex]y=\frac{1}{4}x+b[/tex]

To find the value of b, putting the point (1 -2) in equation

[tex]-2=\frac{1}{4}(1)+b\\-2=\frac{1}{4}+b\\-2-\frac{1}{4}=b\\b=\frac{-8-1}{4} \\b=\frac{-9}{4}[/tex]

Putting the values of b and m

[tex]y=\frac{1}{4}x-\frac{9}{4}[/tex]

A linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) is:

[tex]y=\frac{1}{4}x-\frac{9}{4}[/tex]

Keywords: Equation of line, slope-intercept form

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