Answer:
The linear equation in slope intercept that passes through given points as y = [tex]\frac{1}{4}[/tex] x - [tex]\frac{9}{4}[/tex] .
Step-by-step explanation:
Given points for the line equation as
( - 11 , - 5 ) and ( 1 , - 2 )
The equation of line in slope intercept form as
[tex]y - y_1 = m ( x - x_1)[/tex]
where m is the slope of the line
So , slope can be calculated as
m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Or, m = [tex]\frac{ - 2 + 5 }{1 + 11}[/tex]
Or, m = [tex]\frac{ 3 }{12}[/tex]
∴ m = [tex]\frac{ 1 }{4}[/tex]
Now The equation of line with slope [tex]\frac{ 1 }{4}[/tex] and points is
[tex]y - y_1 = m ( x - x_1)[/tex]
Or, [tex]y+5 = \frac{1}{4} (x + 11)[/tex]
Or, 4 y + 20 = x + 11
Or, 4 y = x + 11 - 20
∴ 4 y = x - 9
I,e y = [tex]\frac{1}{4}[/tex] x - [tex]\frac{9}{4}[/tex]
Hence The linear equation in slope intercept that passes through given points as y = [tex]\frac{1}{4}[/tex] x - [tex]\frac{9}{4}[/tex] . Answer