A koala starts i'm the ground and climbs a Tere yo a height ir 19m.if the koala has a mass of 12 kg,how much gravitational potential energy does ir gain?

Respuesta :

Answer:

The GPE gained by the Koala by climbing a height of [tex]19\ m[/tex] is [tex]=2234.4\ J[/tex]

Explanation:

Gravitational potential energy (GPE) is the energy stored in an object due to its position above the Earth's surface.

This is due to the force of gravity acting on an object.

GPE [tex]= m\times g\times h[/tex],where [tex]g=9.8\ N\ kg^{-1}[/tex]

The units of GPE = Joules [tex](J)[/tex]

Now we have been given.

The mass of the Koala that is [tex]m=12\ kg[/tex]

Height it has climbed is [tex]=h=19\ m[/tex]

And the value of gravity acting on the object [tex]g=9.8\ N\ kg^{-1}[/tex]

Plugging the values of [tex]m,g ,h[/tex] we have

GPE [tex]= mgh=12\times 9.8\times 19=2234.4\ (J)[/tex]

So the gravitational potential energy gained by the Koala [tex]=2234.4\ J[/tex]

Answer:C 2234J

Explanation:

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