Answer:
The molecular formula for oxytetracycline is C₂₂H₂₄O₉N₂
Explanation:
Molar mass oxytetracycline: 460 g/m
Molar mass Carbon: 12 g/m
Molar mass Hydrogen: 1 g/m
Molar mass Oxygen: 16 g/m
Molar mass Nitrogen:
2 grams of compound has:
1.1478 g / 12 g/m = 0.09565 moles of C
0.10435 g / 1 g/m =0.10435 moles of H
0.62609 g / 16 g/m =0.03913 moles of O
2 - 1.1478 - 0.10435 - 0.62609 = 0.12176 g N
0.12176 g / 14g/m = 0.00869 moles of N
By the way, 2 grams of oxytetracycline are 0.00434 moles so
If 0.00434 moles of oxytetracycline have 0.09565 moles of C
1 mol of oxytetracycline, how many moles of C does it has?
0.09565 / 0.00434 = 22 moles of C
0.10435 / 0.00434 = 24 moles of H
0.03913 / 0.00434 = 9 moles of O
0.00869 / 0.00434 = 2 moles of N