Question

What is an equation of the line that passes through the points (-3,-1) and
(-6,3)? Put your answer in fully reduced form.

Answer 1

The equation of line that passes through the points (-3,-1) and

(-6,3) is:

$y=-\frac{4}{3}x-5$

Step-by-step explanation:

Given points are:

(-3,-1) =(x1,y1)

(-6,3)=(x2,y2)

The slope-intercept form of equation of line is:

$y=mx+b$

We have to find the slope first

$m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{3-(-1)}{-6-(-3)}\\=\frac{3+1}{-6+3}\\=\frac{4}{-3}$

Putting the value of slope in the slope intercept form

$y=-\frac{4}{3}x+b$

To find the value of b, putting the point (-3,-1) in the equation

$-1=-\frac{4}{3}(-3)+b\\-1= 4+b\\b=-4-1\\b=-5$

Putting the values of b and m

$y=-\frac{4}{3}x-5$

The equation of line that passes through the points (-3,-1) and

(-6,3) is:

$y=-\frac{4}{3}x-5$

Keywords: Equation of line, slope intercept form

Learn more about equation of line at:

• brainly.com/question/4703807
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