How do you do this question?
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Answer:
C. 1.214
Step-by-step explanation:
P(t) = 2 + 5 tan⁻¹(t/2)
When P(t) = 6, the value of t is:
6 = 2 + 5 tan⁻¹(t/2)
4 = 5 tan⁻¹(t/2)
4/5 = tan⁻¹(t/2)
tan(4/5) = t/2
t = 2 tan(4/5)
t ≈ 2.059
The instantaneous rate of change of P(t) is dP/dt:
dP/dt = 5 / (1 + (t/2)²) × 1/2
dP/dt = 5 / (1 + t²/4) × 1/2
dP/dt = 20 / (4 + t²) × 1/2
dP/dt = 10 / (4 + t²)
At t = 2.059:
dP/dt ≈ 1.214
Here's a graph:
desmos.com/calculator/7leerprg4i