Question

If the specific heat capacity of water is 4.19 J/(g⋅K), how much energy would be required to raise the temperature of 100.0 g of water by 2.00 °C?

Answer 1

Answer:

838 Joules

Explanation:

• To calculate amount of heat required we multiply mass of water by the specific heat capacity and then by change in temperature.
• That is; Q =m×c×ΔT

We are given;

Specific heat capacity of water, c = 4.19 J/g.K

Mass of water, m = 100.0 g

Change in temperature, ΔT = 2.00°C or 2 K

Therefore;

Q = mcΔT

  = 100 g ×  4.19 J/g.K × 2K

  = 838 Joules

Thus, the energy required is 838 Joules