Answer:
Step-by-step explanation:
First, find the mean ; (32+45+33+22+50+48) / 6 = 230/6
Mean = 38.33
Variance =[tex]\frac{SUM(X-meanX)^{2} }{n-1}[/tex]
n = sample size
Variance = [tex]\frac{(32-38.33)^{2} +(45-38.33)^{2}+(33-38.33)^{2} +(22-38.33)^{2}+(50-38.33)^{2}+(48-38.33)^{2} }{5}[/tex]
Variance = [tex]\frac{(44.4889 +40.0689 +28.4089 + 266.6689 +136.1889 +93.5089)}{5}[/tex]
= [tex]\frac{609.3334}{5}[/tex]
= 121.8667
Therefore, variance = 121.87
