Question

My teacher told me to check this problem but I don’t know what I did wrong help please

Answer 1

The equation wouldn’t be y=3x because 1. It’s going down so it would be negative and 2. It doesn’t go down by 3’s because if it was that 2 would be -6. You need to do the equation y=mx + b.

Answer 2

now, let's bear in mind that the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

$\bf \begin{array}{|cc|ll} \cline{1-2} x&y\\ \cline{1-2} 1&-3\\ 2&-9\\ 3&-15\\ 4&-21\\ \cline{1-2} \end{array} \begin{array}{llll} \textit{let's use these points}\\ \leftarrow \\\\ \leftarrow \\\qquad \end{array} ~\hfill (\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-15})$

$\bf \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-15}-\stackrel{y1}{(-3)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{1}}}\implies \cfrac{-15+3}{2}\implies \cfrac{-12}{2}\implies -6$