Question

equation for the line containing (4,5) and (-2,-4)

Answer 1

Answer:

Step-by-step explanation:

first need to find the slope

-4-5=-9

-2-4=-6

=3/2

y-5=3/2(x-4) this is your point slope equation

y-5=3/2x-6

y=3/2x-1 this is your slope intercept equation

-3/2x+y=-1

muliply by -2

3x-2y=2 this is your equation in standard form

Answer 2

Answer:2y - 3x = -2

Step-by-step explanation:

The equation of line in two point form is given as :

$\frac{y-y_{1}}{x -x_{1}}$ = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

from the question,

$x_{1}$ = 4

$x_{2}$ = -2

$y_{1}$ = 5

$y_{2}$ = - 4

substituting into the formula , we have

$\frac{-4-5}{-2-4}$ = $\frac{y-5}{x-4}$

$\frac{9}{6}$ = $\frac{y-5}{x-4}$

$\frac{3}{2}$ = $\frac{y-5}{x-4}$

cross multiplying , we have

2(y-5) = 3(x-4)

2y - 10 = 3x - 12

2y - 3x = -12 +10

2y - 3x = -2