Answer: [tex]t_{n}[/tex] = 3n + 1 , n≥ 1
Step-by-step explanation:
The common difference of the sequence = 3 , so it is an arithmetic sequence.
The formula for the nth term of an arithmetic sequence is given as:
[tex]t_{n}[/tex] = a + (n-1)d
substituting the values of a and d , we have
[tex]t_{n}[/tex] = 4 + (n-1) X 3
[tex]t_{n}[/tex] = 4 + 3n - 3
[tex]t_{n}[/tex] = 1 + 3n
[tex]t_{n}[/tex] = 3n + 1 , n≥ 1