Question

for what values of x does the graph of f(x) have a vertical asymptote? f(x)=3/x²+x-2

a. 1, -2
b. 3, 0
c. 3, -2
d. -1, 2

Answer 1

Answer:

a. 1, -2

Step-by-step explanation:

$f(x)=\frac{3}{x^{2}+x-2}\\f(x)=\frac{3}{(x+2)(x-1)}$

Find when the denominator equates to 0.

x+2 = 0

x = -2

x-1 = 0

x = 1

Set restrictions for x in the denominator to find the vertical asymptotes

x ≠ -2, 1