Question

The sum of 3 numbers is 145. Seven times the second number is twice the first number and twice the second number is six times the third number.


Find the ratio of the product of the first and the third numbers to the square of the second number.
will give brainlyest

Answer 1

Answer:

$\frac{7}6}$

Step-by-step explanation:

Let the 3 numbers be $x,y,$ and $z$

As per question,

$x+y+z=145$

Also, 7 times the second number is twice the first, so

$7y=2x\\\frac{x}{y}=\frac{7}{2}----------- 1$

Again, twice the second number is 6 times the third number, so

$2y=6z\\\frac{2}{6}=\frac{z}{y}\\\frac{z}{y}=\frac{1}{3}---------- 2$

Now, multiply equations 1 and 2. This gives,

$\frac{x}{y}\times \frac{z}{y}=\frac{7}{2}\times \frac{1}{3}\\\frac{x\times z}{y\times y}=\frac{7\times 1}{2\times 3}\\\frac{xz}{y^2}=\frac{7}{6}$

Therefore, the ratio of the product of the first and the third numbers to the square of the second number is $\frac{7}6}$