Answer:
Pb(NO3)2+2NaCl \to PbCl2+NaNO3
Explanation:
Lead(II) nitrate is [tex]$Pb(NO_{3})_{2}$[/tex]
Sodium Chloride is [tex]$NaCl$[/tex]
This is a double displacement reaction. Hence anions or cations of both the compounds are displaced to form the products.
[tex]Pb^{+2}$ and $Cl^{-}$ combine to form PbCl_{2}[/tex]
[tex]Na^{+} and \,NO_{3}^{-} combine\, to\, form\, NaNO_{3}[/tex]
Therefore the balanced equation is
[tex]Pb(NO_{3})_{2}(aq)+2NaCl(aq) \to PbCl_{2}(s)+2NaNO_{3}(aq)[/tex]
