Respuesta :

Answer:

[tex]y-8x=-8[/tex] is the equation in standard form.

Step-by-step explanation:

Lets choose two coordinate point from the graph [tex](x_1,y_1) =(0,-8)[/tex][tex](x_2,y_2)=(2,8)[/tex].

Now we will try to find out its slope from point-slope form.

Slope (m) =[tex]\frac{y_2-y_1}{x_2-x_1} =\frac{8-(-8)}{2-0}=\frac{16}{2} = 8[/tex]

No we will use [tex]y-y_1 =m(x-x_1)[/tex]

So [tex]y-8=8(x-2)\ , y-8=16x-16\ , y=16x-16+8[/tex]

Now this can be arranged in Ax+By=C form that is the standard form of a line.

Re-arranging the values.

We have [tex]y-8x=-8[/tex] as our equation in standard form.

Answer:

The required standard equation is [tex]y = 8x -8[/tex].

we took two points to write this equation (0,-8) and (2,8).

Step-by-step explanation:

Let [tex](0,-8) = (x1,y1)\\(2,8) = (x2,y2)[/tex]

The equation of line passing through two point is given as

[tex](y - y1) = \frac{y2-y1}{x2-x1} \times (x - x1)\\[/tex]

substituting (x1,y1) and (x2,y2) in above equation we get

[tex](y - -8) = \frac{8--8}{2-0} \times (x - 0)\\[/tex]

[tex](y + 8) = \frac{8+8}{2} \times (x)\\[/tex]

[tex](y + 8) = \frac{16}{2} \times (x)\\[/tex]

[tex](y + 8) = 8\times (x)\\[/tex]

[tex]y = 8x - 8\\[/tex]

which is the required equation