Use the information on the graph to enter an equation in standard form.?
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Answer:
[tex]y-8x=-8[/tex] is the equation in standard form.
Step-by-step explanation:
Lets choose two coordinate point from the graph [tex](x_1,y_1) =(0,-8)[/tex][tex](x_2,y_2)=(2,8)[/tex].
Now we will try to find out its slope from point-slope form.
Slope (m) =[tex]\frac{y_2-y_1}{x_2-x_1} =\frac{8-(-8)}{2-0}=\frac{16}{2} = 8[/tex]
No we will use [tex]y-y_1 =m(x-x_1)[/tex]
So [tex]y-8=8(x-2)\ , y-8=16x-16\ , y=16x-16+8[/tex]
Now this can be arranged in Ax+By=C form that is the standard form of a line.
Re-arranging the values.
We have [tex]y-8x=-8[/tex] as our equation in standard form.
Answer:
The required standard equation is [tex]y = 8x -8[/tex].
we took two points to write this equation (0,-8) and (2,8).
Step-by-step explanation:
Let [tex](0,-8) = (x1,y1)\\(2,8) = (x2,y2)[/tex]
The equation of line passing through two point is given as
[tex](y - y1) = \frac{y2-y1}{x2-x1} \times (x - x1)\\[/tex]
substituting (x1,y1) and (x2,y2) in above equation we get
[tex](y - -8) = \frac{8--8}{2-0} \times (x - 0)\\[/tex]
[tex](y + 8) = \frac{8+8}{2} \times (x)\\[/tex]
[tex](y + 8) = \frac{16}{2} \times (x)\\[/tex]
[tex](y + 8) = 8\times (x)\\[/tex]
[tex]y = 8x - 8\\[/tex]
which is the required equation