Respuesta :
Answer:
The airplane should release the parcel [tex]6.7*10^2[/tex] m before reaching the island
Explanation:
The height of the plane is [tex]y_0=100m[/tex], and its speed is v=150 m/s
When an object moves horizontally in free air (no friction), the equation for the y measured with respect to ground is
[tex]y=y_0 - \frac{gt^2}{2}[/tex] [1]
And the distance X is
x = V.t [2]
Being t the time elapsed since the release of the parcel
If we isolate t from the equation [1] and replace it in equation [2] we get
[tex]X = V . \sqrt{\frac{2y_0}{g}}[/tex]
Using the given values:
[tex]x = 150 m/s \sqrt{\frac{2\times 100m}{9.8 m/sec^2}}[/tex]
x = [tex]6.7*10^2[/tex] m
We have that for the Question "An airplane is delivering food to a small island. It flies 100 m above the ground at a speed of 150 m/s ." it can be said that the distance of release is given as
d=623.7m
From the question we are told
An airplane is delivering food to a small island. It flies 100 m above the ground at a speed of 150 m/s .
Where should the parcel be released so it lands on the island? Neglect air resistance.
Generally the equation for the is mathematically given as
[tex]S=ut+\frac{1}{2}at^2\\\\Where\\\\100=0-\frac{1}{2}*9.8t^2\\\\t=4.518sec\\\\[/tex]
Therefore
The distance of release is given as
d=150*4.158
d=623.7m
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