Question

Use synthetic division to determine if x+2 is a factor of f(x)=5x2+13x+6

Answer 1

Answer:

x+2 is a factor of $f(x)  = 5x^2 + 13x + 6$

Step-by-step explanation:

To check: If (x+2) is a a factor of the polynomial $f(x)  = 5x^2 + 13x + 6$

We need to check if x  = -2 is the FACTOR of the given polynomial.

⇒ To show:  f (-2)  =  0

Now

$f(-2)  = 5(-2)^2 + 13(-2) + 6\\=5(4) -26 + 6\\= 20 + 6 - 26\\= 26 - 26  = 0\\\implies f(-2) = 0$

Since, f(-2) = 0

⇒  -2 is the ROOT of the Polynomial f(x).

⇒(x +2) is the factor of the given polynomial.

Hence, x+2 is a factor of $f(x)  = 5x^2 + 13x + 6$