Answer:
Expression in [tex]n^{th}[/tex] term is [tex]T_n =2(6-n)[/tex]
Step-by-step explanation:
Arithmetic sequence 10,8,6,4,.....
first term a = 10
second term = 8
number of terms = n
common difference d = Second term - First term = [tex]8-10 \ =\ -2[/tex]
Now by using Arithmetic Progression Formula which states
[tex]T_n = a+(n-1)d[/tex]
Substituting given values in the above expression we get
[tex]T_n= 10+((n-1)\times-2})= 10-2n+2= 12-2n= 2(6-n)[/tex]