Answer:
The required probability is [tex]\simeq 0.26214[/tex]
Step-by-step explanation:
There were 4,065,014 births in a given year and of those births 2,081,287 were boys and 1.983,727 were girls.
So, P(both children will be boys) = [tex]\frac {^{2081287}{C}_2}{^{4065014}{C}_{2}}[/tex]
[tex]\simeq 0.26214[/tex]