Answer:
The correct answer is option B
Explanation:
[tex]$Molarity=\frac{Weight}{Molecular \,weight} \frac{1000}{V(in \, ml)}[/tex]
Given values,
Molarity of [tex]$FeCl_3=0.100M$[/tex]
Volume of solution, [tex]$V=250ml$[/tex]
Molecular weight of [tex]$FeCl_3=162.2$[/tex]
Substituting this values in Molarity formula, we get
[tex]$0.1=\frac{weight}{162.2} \times\frac{1000}{250} $\\$\Rightarrow 16.22=weight\times4$\\$\Rightarrow weight=\frac{16.22}{4} $\\$\therefore weight=4.06g$[/tex]
