Answer:
B, C, F
Step-by-step explanation:
Given:
[tex]\left\{\begin{array}{l}4x+3y=12\\ \\2x+3y=-6\end{array}\right.[/tex]
Subtract the second equation from the first equation:
[tex](4x+3y)-(2x+3y)=12-(-6)\\ \\4x+3y-2x-3y=12+6\\ \\2x=18\\ \\x=9[/tex]
Option B "The x coordinate of the solution is 9" is ture
Substitute it into the first equation:
[tex]4\cdot 9+3y=12\\ \\36+3y=12\\ \\3y=12-36\\ \\3y=-24\\ \\y=-8[/tex]
Option F "The y coordinate of the solution is -8" is true.
Point (9,-8) is in the IV quadrant, so option C is true.