Question

How many carbon monoxide molecules are in 3.36 L of carbon monoxide gas at RTP?

Answer 1

8.43 × 10²² carbon monoxide molecules

Explanation:

At RTP conditons we use the the following formula to find the number of moles of a gas:

number of moles = volume / 24 (L/mole)

number of moles of carbon monoxide = 3.36 / 24 = 0.14 moles

Now we use Avogadro's number to calculate the number of carbon monoxide molecules:

if in 1 mole of carbon monoxide there are 6.022 × 10²³ carbon monoxide molecules

then in 0.14 moles of carbon monoxide there are X carbon monoxide molecules

X = (0.14 × 6.022 × 10²³) / 1 = 0.843 × 10²³ = 8.43 × 10²² carbon monoxide molecules

Learn more about:

Avogadro's number

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