Answer:
They will work for [tex]17\dfrac{1}{7}[/tex] minute [tex]\simeq 17.14[/tex] minute together to finish the work.
Step-by-step explanation:
In 45 minutes Sue cleans the whole room
So, in 1 minute Sue does [tex]\frac {1}{45}[/tex] part of the total work -------(1)
so in 15 minutes Sue does [tex]\frac {1 \times 15}{45}[/tex]
= [tex]\frac {1}{3}[/tex] part of the total work -------------------------(2)
So, the amount of work left, = (1 - 1/3)
= 2/3 of the total work.
In 60 minutes, Ann cleans the whole room
so,in 1 minute Ann does [tex]\frac{1}{60}[/tex] of the total work.
So, in 1 minute, Ann and Sue together do,
[tex]\frac{1}{45} +\frac{1}{60}[/tex]
= [tex]\frac{4 + 3}{180}[/tex]
= [tex]\frac {7}{180}[/tex] of the total work.
So, Ann and Sue together do [tex]\frac {7}{180}[/tex] of the total work in 1 minute.
So, they would have done the whole work in, [tex]\frac {180}{7}[/tex] minute.
So, they would do [tex]\frac{2}{3}[/tex] of the total work in
[tex]\frac{180 \times 2}{3 \times 7}[/tex] minute
= [tex]\frac{120}{7}[/tex] minute
= [tex]17\dfrac{1}{7}[/tex] minute
[tex]\simeq 17.14[/tex] minute