In isosceles triangle ∆ABC, BM is the median to the base AC . Point D is on BM . Prove the following triangle congruencies: ∆AMD ≅ ∆CMD.

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Answer:

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Step-by-step explanation:

In isosceles triangle ∆ABC, BM is the median to the base AC.

Since ΔABC is isosceles, then AB ≅ BC.

Since BM is the median, then AM ≅ MC.

Consider triangles ABM and CBM. In these triangles,

  • AB ≅ BC;
  • AM ≅ MC;
  • BM ≅ BM (reflexive property).

So, ΔABM ≅ ΔCBM by SSS postulate. Congruent triangles have conguent corresponding sides and angles, so

∠AMB ≅ ∠CMB.

Consider triangles AMD and CMD. In these triangles,

  • ∠AMB ≅ ∠CMB;
  • AM ≅ MC;
  • MD ≅ MD (reflexive property),

so ΔAMD ≅ ΔCMD by SAS postulate

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