Answer:
See explanation
Step-by-step explanation:
In isosceles triangle ∆ABC, BM is the median to the base AC.
Since ΔABC is isosceles, then AB ≅ BC.
Since BM is the median, then AM ≅ MC.
Consider triangles ABM and CBM. In these triangles,
So, ΔABM ≅ ΔCBM by SSS postulate. Congruent triangles have conguent corresponding sides and angles, so
∠AMB ≅ ∠CMB.
Consider triangles AMD and CMD. In these triangles,
so ΔAMD ≅ ΔCMD by SAS postulate