Answer:
Step-by-step explanation:
You have to find the slope
Slope= y₂ - y₁ / x₂-x₁
A(3, -3), B(2, 1)
Slope of AB m₁ = 1-[-3] / 2-3 = 1+3 / -1 = 4/-1 = -4
B(2, 1) ; C(7, -2)
slope of BC m₂= -2-1 / 7-2 = -3/5
A(3, -3) ; C(7, -2)
Slope of AC m₃ = -2-[-3] / 7-3 = -2+3 / 4 = 1/4
m₁ * m₃ = -4 * (1/4) = -4/4 = -1
When the product of slope is (-1), then two lines are perpendicular.
So AB and AC are perpendicular. Δ ABC is a right-angled triangle
