Answer:
Yes, he will have enough 3 over 8 ft pieces for his class.
Step-by-step explanation:
Given:
Number of wood required = 22
Length of each wood, [tex]l=\frac{3}{8}\textrm{ ft}[/tex]
Total length of the board, [tex]L=9\textrm{ ft}[/tex]
Therefore, the number of woods that can be made using the given board is given as:
[tex]\textrm{Number of woods made}=\frac{\textrm{Total length of board}}{\textrm{Length of each wood}}\\\textrm{Number of woods made}=\frac{L}{l}=\frac{9}{\frac{3}{8}}=9\times \frac{8}{3}=\frac{72}{3}=24[/tex]
So, he can make 24 woods of length [tex]\frac{3}{8}\textrm{ ft}[/tex] using the 9 ft board. But he has to make only 22 pieces.
Therefore, he has enough of the wood to make the required number of pieces.