Answer:
Hence proved Δ AMD ≅ Δ CMD by SAS rule
Step-by-step explanation:
Given:
Triangle in the attachment.
Δ ABC is an Isosceles triangle
∠ A = ∠ C, AB = BC
Segment BM is median to base segment AC
∴ AM= MC
Solution
Now by Side-Angle-Side congruent property
Δ ABM ≅ Δ CBM
∴ ∠ BMA = ∠ BMC
∴ ∠ DMA = ∠ DMC
Now, In Δ AMD and Δ CMD
AM = MC (median)
∠ DMA = ∠ DMC (DM is Common in both)
Hence By S.A.S
Δ AMD ≅ Δ CMD hence proved
