Respuesta :
There are 9 cans of soup and 5 cans of frozen dinner.
The variables used for soup and frozen dinner are x and y respectively.
Step-by-step explanation:
Let,
Soup = x
Frozen Dinner = y
According to given statement of sodium;
300x + 500y = 5200 eqn 1
And,
x + y = 14 eqn 2
[tex]Multiplying\ equation\ 2\ with\ 300\\300(x+y=14)\\300x+300y=4200\ Eqn 3\\[/tex]
Subtracting Eqn 3 from Eqn 1;
[tex](300x+500y)-(300x+300y)=5200-4200\\300x+500y-300x-300y=1000\\200y=1000\\y=\frac{1000}{200} \\y=5[/tex]
Putting value of y in Eqn 1;
[tex]300x+500(5)=5200\\300x+2500=5200\\\\Subtracting\ 2500\ from\ both\ sides\ \\300x+2500-2500=5200-2500\\300x=2700\\x=\frac{2700}{300} \\x=9[/tex]
There are 9 cans of soup and 5 cans of frozen dinner.
The variables used for soup and frozen dinner are x and y respectively.
Keywords: Variables, linear equations, subtraction.
Learn more about linear equations at;
- brainly.com/question/5047646
- brainly.com/question/5048216
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