Answer:
The area of sector with radius 3 cm and angle at center is [tex]\frac{9\pi }{8}[/tex] cm²
Step-by-step explanation:
Given as :
The radius of circle = 3 cm
The angle at the center of circle = Ф = [tex]\frac{\pi }{4}[/tex] = 45°
Now, Area of sector = [tex]\frac{\Pi r^{2}\times \Theta }{360}[/tex]
Or, Area of sector = [tex]\frac{\Pi 3^{2}\times \ 45° }{360°}[/tex]
Or, Area of sector = [tex]\frac{\Pi 9\times \ 45° }{360°}[/tex]
Or, Area of sector = [tex]\frac{\Pi times \ 45° }{40°}[/tex]
Or, Area of sector = [tex]\frac{9\pi }{8}[/tex] cm²
Hence The area of sector with radius 3 cm and angle at center is [tex]\frac{9\pi }{8}[/tex] cm² Answer