Question

Use the elimination method to solve the following system of equations.
4x - 12y = 0
x + 3y = 7

Answer 1

For this case we have the following system of equations:

$4x-12y = 0\\x + 3y = 7$

To solve, we follow the steps below:

We multiply the second equation by -4:

$-4x-12y = -28$

We add the equations:

$4x-4x-12y-12y = 0-28$

Equal signs are added and the same sign is placed.

$-24y = -28\\y = \frac {-28} {- 24}\\y = \frac {14} {12} = \frac {7} {6}$

We look for the value of the variable "x":

$x = 7-3y\\x = 7-3 \frac {7} {6}\\x = 7- \frac {21} {6}\\x = \frac {42-21} {6}\\x = \frac {21} {6}\\x = \frac {7} {2}$

Thus, the solution of the system is:

$(x, y): (\frac {7} {2}; \frac {7} {6})$

Answer:

$(x, y): (\frac {7} {2}; \frac {7} {6})$

Answer 2

Answer:

x= 7/2        y = 7/6

Step-by-step explanation:

4x - 12y = 0

x + 3y = 7

Multiply the second by( -4) to eliminate the X variable

4x - 12y = 0

-4x -12y=  -28

ADD BOTH

-24y=-28

Divide both by  -24

y= 28/24

y=7/6

Plug y into  second equation

x + 3y = 7

x+ 3(7/6) = 7

x+21/6=7

x+7/2=7

x=7-(7/2)

x=( 14/2) - (7/2)

x= 7/2