Respuesta :
Answer:
First part:
1) The probability of this person having type AB blood is 4% because this is the proportion of the U.S. population that has type AB blood. This is calculated by adding the proportion ot the U.S. population that has type O blood with the proportion that has type A blood and the proportion that has type B blood and then finding out the value for us to complete the 100%.
45% + 40% + 11% = 96%
2) In this case we must use the addition rule:
P(A or B) = P(A) + P(B) - P(A and B)
In this case A is the event that the person has type A blood. B is the event that the person has type B blood.
P(A)= 40%
P(B) = 11%
P(A and B)= 0 because you cannot hay type A and type B blood at the same time.
P(A or B) =51%
3) The probability that the person has not type O blood is going to be the same as the proportion of the U.S. population that doesn't have type O blood.
100% - 45% = 55%
Second part:
In this case we have 4 trials. Each trial is independent so we can use the multiplication rule.
P( A and B and C and D)= P(A) x P(B) × P(c) × P(D)
1) P( O and O and 0 and O) = 0.45 × 0×45×0.45×0.45 = 0.041 = 4.1%
2) 0,96× 0.96 × 0.96 × 0.96 = 0.85 = 85%
3) In this case we need to add the probability that 1 of them is type B plus the probability that 2 of them are type B plus the probability that 3 of them are type B plus the probability that the tour of them are type B
The probability of being type B is 11% = 0.11
The probability of not being type Bis 89%=0.89
0.11 × 0.89 X 0.89 × 0.89 = 0.078 = 7.8%
0>11 × 0.11 × 0.89×0.89 = 0.0096 = 0.96%
0.11 × 0.11 × 0.11 × 0.89 = 0.0012 = 0.12%
0.11×0.11×0.11×0.11 = 0.00015 = 0.015%
7.8% + 0.96% + 0.12% + 0.015% = 8.895%