Answer:
The distance cover by him walking back is 11.25 miles
Step-by-step explanation:
Given as :
Time for Janelle to spend on training = 5 hours
The running speed of Janelle = 9 mph
The walking back with 3 mph
Let The distance for running and walking is same i.e D miles
SO, Time = [tex]\frac{Distance}{Speed}[/tex]
∴ 5 = [tex]\frac{D}{9}[/tex] + [tex]\frac{D}{3}[/tex]
Or, 5 × 9 = D + 3 D
Or, 45 = 4 D
∴ D = [tex]\frac{45}{4}[/tex] = 11.25 miles
Hence The distance cover by him walking back is 11.25 miles Answer