A circular-motion addict of mass 77 kg rides a Ferris wheel around in a vertical circle of radius 10 m at a constant speed of 5.6 m/s. (a) What is the period of the motion? 11.2 Correct: Your answer is correct. s (b) What is the magnitude of the normal force on the addict from the seat when both go through the highest point of the circular path?

Respuesta :

Answer:

a) 11.21 m/s

b) 513.89 N

Explanation:

mass of addict = 77 kg

radius of circle= 10 m

velocity of circular motion v =5.6 m/s

a)time period of motion

T= 2πr/v = 2×3.14×10/5.6 = 11.21 sec

b) At the highest point normal reaction force F_N is upward

the gravitational force F_g  is downward and centripedal force mv^2/r is upward

F_N= F_g - mv^2/r

= 77*9.81- 77*5.6^2/10

= 513.89 N